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Scott Spence

JavaScript snippets from around the web

3 min read
Hey! Thanks for stopping by! Just a word of warning, this post is almost 5 years old, wow! If there's technical information in here it's more than likely out of date.

This is a dump of all the snippets I have collected over the last 18 months or so, that I’m going to document here so it’s probably going to be a mess but it’s mainly for my reference so 😛

Arrays

Straight from Wes himself.

🔥 The Array .some() Method is super handy for checking if at least one item in an array meets what you are looking for

const user = {
  name: 'Dave',
  permissions: ['USER', 'CREATE_ITEM'],
}

// check if the user is either admin or can delete in item
const canDelete = user.permissions.some(p =>
  ['ADMIN', 'DELETE_ITEM'].includes(p)
)
// canDelete is false

// check if a user is either admin or can create in item
const canCreate = user.permissions.some(p =>
  ['ADMIN', 'CREATE_ITEM'].includes(p)
)
// canDelete is true

On the same note .every() is great for checking every item in an array meets what you are looking for.

const people = [
  { name: 'Dave', age: 42 },
  { name: 'Sue', age: 26 },
  { name: 'India', age: 9 },
]

const canEveryoneDrink = people.every(p => p.age >= 18)
// false

const canSomeoneDrink = people.some(p => p.age >= 18)
// true

const howManyDrinkers = people.filter(p => p.age >= 18).length
// 2

Via Addy Osmani

Get the unique values of an array in JS. Use ES2015 Set() and ...rest to discard duplicate values.

const uniqueArray = arr => [...new Set(arr)]

uniqueArray([1, 1, 2, 2, 3, 3, 4, 4, 5, 5, 6, 6, 7, 7, 0, 0, 10, 10])
// Array(9) [ 1, 2, 3, 4, 5, 6, 7, 0, 10 ]
uniqueArray([
  'London',
  'Manchester',
  'Cambridge',
  'London',
  'Greater London',
  'London',
  'Manchester',
])
// Array(4) [ "London", "Manchester", "Cambridge", "Greater London" ]

Array.from() accepts another .map arguments. Useful for calling each element of a created array.

const year = new Date().getFullYear()
const totalYears = 5

Array.from('web')
// Array(3) [ "w", "e", "b" ]

Array.from(Array(totalYears), (_, i) => year + i)
// Array(5) [ 2019, 2020, 2021, 2022, 2023 ]

Array.from({ length: totalYears }, (_, i) => year + i)
// Array(5) [ 2019, 2020, 2021, 2022, 2023 ]

Async await

const getAsyncStuff = async name => {
  try {
    const response = await fetch(
      `https://api.github.com/users/${name}`
    )
    return await response.json()
  } catch (err) {
    console.error(err)
  }
}

🔥 4 Ways to handle the double promise with fetch() and async+await

const url = 'https://api.github.com/users/spences10'

async function go() {
  // 1. tac a promise onto the end
  const p1 = await fetch(url).then(data => data.json())

  // 2. double
  const p2 = await (await fetch(url)).json()

  // 3. capture promise in a variable
  const data = await fetch(url)

  // then convert it on another line
  const p3 = await data.json()

  // 4. create a utility function
  const p4 = await getJSON(url)
}

// use ... spread to get all arguments
function getJSON(...butter) {
  // then spread into the fetch function
  return fetch(...butter).then(data => data.json())
}

go()

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